How to convert sync codes to be async one
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Method1:
- create a future object
- define a callback function which will continue check future result is ready or not, future.set_result() will be invoked when future result is ready, else schedule the callback to be called again in the even loop
- in main function, start the callback function the first time, so it will continue executing until the future result is set
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use await keyword to evaluate the future object until it is ready
event_loop = asyncio.get_event_loop() def retreive_from_db(future, id): # it should have a async result or other flag which indicate we get the result from db or not operation_flag = get_from_db(id) # if the flag is ready, then we assume we already get real result, set the future to the real result if operation_flag.ready(): future.set_result(real_result) # else we scheduler to check operation done flag later else: event_loop.call_soon(retreive_from_db, future, id) def main(): # create a future object and pass to callback function db_result = asyncio.Future() # scheduler the callback in event loop the first time event_loop.call_soon(retreive_from_db, db_result, id) # wait untile the db_result get the real result final_result = await db_result
Below is a rewrite of Tornado implementation of celery result retrieving in Sanic:
from celery import Celery celeryapp = Celery() celeryapp.config_from_object('celeryconfig') app = Sanic(__name__) def retrieve_task_result(event_loop, task_result, async_result): if async_result.ready(): task_result.set_result(async_result.get()) else: event_loop.call_soon(retrieve_task_result, event_loop, task_result, async_result) async def send_task(request_body): return celeryapp.send_task('tasks.test', (request_body,)) @app.route('/', methods=['POST']) async def main(request): request_body = request.body.decode('utf-8') async_result = await send_task(request_body) event_loop = asyncio.get_event_loop() task_result = asyncio.Future() event_loop.call_soon(retrieve_task_result, event_loop, task_result, async_result) ret = await task_result return text(ret) if __name__ == "__main__": app.run(host="0.0.0.0", port=8080, debug=False) -
Method2
- encapsulate the sync function to be Future object, in asyncio, it can use asyncio.ensure_future() or asyncio.get_event_loop().create_task(). Or you are expert, you can use asyncio.Task(somefunc(id)) directly
e,g: For below synchonize codes
def handle(id): subject = get_subject_from_db(id) buyinfo = get_buyinfo(id) change = process(subject, buyinfo) notify_change(change) flush_cache(id)We can converted to below one:
import asyncio import time async def get_subject_from_db(id): time.sleep(3) return "subject" async def handle(id): # turn blocked I/O function to be future object subject = asyncio.ensure_future(get_subject_from_db(id)) buyinfo = asyncio.ensure_future(get_buyinfo(id)) # explicitly announce future task can be schedulered in event loop results = await asyncio.gather(subject, buyinfo) # explicitly announce process() can be schedulered in event loop change = await process(results) await notify_change(change) loop.call_soon(flush_cache, id) -
Conclusion
- encapsulate the sync function to be Future object, in asyncio, it can use asyncio.ensure_future() or asyncio.get_event_loop().create_task(). Or you are expert, you can use asyncio.Task(somefunc(id)) directly
- use callback method, e,g:
- asyncio.get_event_loop().call_soon(func, *args)
- asyncio.get_event_loop().call_later(delay, func, *args)
- asyncio.get_event_loop().call_at(when, func, *args)
References: